1/3(x+5)^2=7

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Solution for 1/3(x+5)^2=7 equation: 


x in (-oo:+oo)

(1/3)*(x+5)^2 = 7 // - 7

(1/3)*(x+5)^2-7 = 0

1/3*(x+5)^2-7 = 0

1/3*(x+5)^2-7 = 0

1/3*x^2+10/3*x+4/3 = 0

1/3*x^2+10/3*x+4/3 = 0

1/3*(x^2+10*x+4) = 0

x^2+10*x+4 = 0

DELTA = 10^2-(1*4*4)

DELTA = 84

DELTA > 0

x = (84^(1/2)-10)/(1*2) or x = (-84^(1/2)-10)/(1*2)

x = (2*21^(1/2)-10)/2 or x = (-2*21^(1/2)-10)/2

1/3*(x-((-2*21^(1/2)-10)/2))*(x-((2*21^(1/2)-10)/2)) = 0

1/3*(x-((-2*21^(1/2)-10)/2))*(x-((2*21^(1/2)-10)/2)) = 0

( x-((-2*21^(1/2)-10)/2) )

x-((-2*21^(1/2)-10)/2) = 0 // + (-2*21^(1/2)-10)/2

x = (-2*21^(1/2)-10)/2

( x-((2*21^(1/2)-10)/2) )

x-((2*21^(1/2)-10)/2) = 0 // + (2*21^(1/2)-10)/2

x = (2*21^(1/2)-10)/2

x in { (-2*21^(1/2)-10)/2, (2*21^(1/2)-10)/2 }

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